Determine Voltage Drop Across Resistors 2013-03-02
2013年3月2日 · Vx = Voltage (x = Current Value across X Resistor) Rx = Resistor value(x = resistor#) V = I x Rx V1 = .53 mA x 2k V1 = 1.06V V2 = .53 mA x 5k V2 = 2.65 V3 = .53 mA x 10k V3 = 5.3V V1 + V2 + V3 = 9.01 (voltage is 9V only 9.01 because i rounded up from .529 to .53) At .529 you can see barely a difference: V1=1.058V V2=2.645V V3=5.290V V Total= 8.993V
LTspice confusing resistor current reference direction
2019年10月21日 · It is well-known that rotating a resistor in LTspice by 180 degrees will change the reference current direction through this resistor, and the voltage across and current through this resistor will appear to be 180 degrees out of phase. I don't think this has anything to do with the so-called passive sign convention.
How a resistor works at the atomic level. Why does voltage drop …
2017年1月23日 · If voltage is the line integral of the electric field with respect to distance, then we multiply the electric field at each point by an infinitesimal distance dr, and add the small pieces of voltage together to find the total voltage drop. This can of course be divided into a sum of integrals or voltage drops across the resistor.
Series Circuit Maximum Voltage of a Resistor
2015年3月22日 · A 1-kΩ ¼ W resistor and a 1.5-kΩ 1/8 W resistor are in series. What is the maximum amount of voltage that can be applied to this circuit without exceeding the wattage rating of either resistor? My calculations are: V = sqrt(0.25 x 1000) V1 = 15.811 V = sqrt(0.125 x 1500) V2 = 13.693 Vmax = 15.811 + 13.693 Vmax = 29.504 is my answer
Bad calculation... | Electronics Forum (Circuits, Projects and ...
2024年9月21日 · Measured the voltage across a 10 Ω resistor placed in series with the fan motor = 4VAC That means 120V across the fan motor with current of 0.4 A trough both. That means the motor impedance is 300 Ω A plain 300 Ω resistance ( as a light bulb of 120V 48 W ) in series will allow to work on 240VAC
Voltage follower with feedback resistor? | Electronics Forum …
2024年3月8日 · e.g. << 0.25A for 1/4W or 5A for 5W. @ 150'C so the current sense R is normally derated by 50% for power to reduce temp rise by 50%. Likewise the FET drops from 12V voltage and dissipate >10X more heat than R14 so the DAC output voltage must be limited much less than 0.5V, I expect, unless the FET has a massive heatsink.
Variable Resistor and Capacitor in a circuit
2013年9月7日 · That's the voltage across the cap. So just because we made the resistor time variable we went from an equation like A*(1-e^(-a*t)) to the equation above for v(t). And that time variable resistor was one of the simpler possible forms for a time variable resistor. Who knows what we would end up with if we made it a more complicated function.
Controlling current through a relay coil using resistors
2010年10月12日 · Your source voltage is 13.8 volts. So we have 13.8 - 5.0 = 8.8 volts and that gets us to 8.8 volts / .072 amp = 122Ω. You want to place a 120 Ohm (you won't find 122Ω) resistor in series with your relays. The power is voltage * current so 8.8 * .072 = .634 watt. I would use 120 Ohm 1 Watt resistors in series with the relay coils. Ron
Voltage rises across piezo buzzer when connected!
2022年9月21日 · This is an easy EMI stability test for any power supply by creating a short current spike that affects the FB voltage compensation filter to raise the voltage. Congrats. ;>} The HPM24BX-1 piezo buzzer only draws an average of 2.5mA @ 5V but the impulse current may be >>10x higher for << 1/10x 100% of the duration of its 2800 Hz or 357 / 2 us ...
Voltage divider, High Ohm resistors vs. Low Ohm
2010年12月26日 · The circuit itself becomes the "bottom resistor" in the divider. The amount of voltage dropped across said resistor is equal to the product of the current drawn by said circuit and the resistor's value in Ohms (Ohm's Law...E = I x R). However, when you add a circuit across the bottom resistor in a voltage divider, you decrease its effective value.