Impossible to understand factoring polynomials. : r/learnmath
2022年9月1日 · Here’s the crucial fact: when using real numbers some quadratic polynomials factor and others do not! It all depends on the discriminant, which is a number associated to the function. A quadratic polynomial is ax 2 +bx+c, where a, b and c are any three numbers and a is not zero (if it were, then the polynomial wouldn’t actually be degree two!).
Anyone else think there's way to much emphasis on factoring …
sure, it isn't the fastest way to find roots. but factoring polynomials is the first time we see something behave like the integers that isn't the integers, in that we can uniquely break up elements into their essential parts, with prime numbers and irreducible polynomials respectively. this connection (and other shared properties between ...
Serious issues understanding how to factor polynomials.
2024年3月15日 · I am at the section where I have to factor polynomials with a leading coefficient other than 1. This section showcases different methods for handling different types of polynomials. I understand how to factor numbers and whatnot but I am getting analysis paralysis when handling different types of polynomials and I think I've reached a limit ...
How in the world do you factor polynomials intuitively?! - Reddit
2023年8月15日 · for polynomials of the form ax 2 +bx+c, you can take a look at the factors of a and c, for example a = mn and c = rs, and see if b can be written as the form b = ms+nr. Also, sometimes a polynomial can just be rewirtten in the form p 2 x 2 +2pqx+q 2 = (px+q) 2 and such.
[Algebra 2] Factoring polynomials, I don't get it at all
2017年6月10日 · The polynomials (with real number, or better yet, complex number coefficients) are algebraically very, very similar to the integers. We can factor the integers into primes. The primes are the "atoms" of the numbers. Similarly, we can factor polynomials into irreducibles. These are the "atoms" of the polynomials.
What is the best way to factor a cubic polynomial? : r/learnmath
Step 1: The Rational Root Theorem is your friend. It says that for any rational root of a polynomial, the numerator of the root is a factor of the constant term, and the denominator is a factor of the leading coefficient. So if your cubic is, say, 2x 3 + x - 3, then any rational roots have a 1 or 3 in the numerator and a 1 or 2 in the ...
I cannot factor polynomials for the life of me : r/learnmath - Reddit
2019年3月29日 · Yes, factoring polynomials are extremely important, keep practicing. You could always try multiplying your answer out in your head to see if it is correct. Here is a good way to do it E: Factor 2x^2+5x+3 Using vieta's, we must have two numbers that multiply to 6 and adds up to 5. Now, using trial and error, you can figure out that it is 2 and 3.
Why is factoring polynomials so hard? : r/mathematics - Reddit
Just use the quadratic formula. Factoring cubic polynomials is much more involved; factoring quartic polynomials is pretty much as complicated as cubic polynomials, and factoring polynomials of higher powers is actually impossible, mathematically. At least this is true in one variable. With polynomials in more than one variable, all bets are off.
Is there a list to go through when factoring polynomials? : r/math
2019年1月29日 · When polynomials become too large and unwieldy, generally, from the perspective of a mathematical numerical analyst, he/she would numerically approximate solutions to the polynomial. The simplest known such method is the Newton-Raphson method, however, this does not work for all continuous functions (with sufficiently continuous derivatives).
How can I understand factoring polynomials more? : r/learnmath
2024年4月30日 · Since the remainder is 0, x-1 is a factor and 1 is a zero. We can also see that the unfactored part is 2x 2 –23x+30. So we now know that: 2x 3 – 25x 2 + 53x – 30 = (x – 1)(2x 2 – 23x + 30) To factor the trinomial we can use the quadratic formula but I'll try the guess and check method first.